Question:
In the Young's double slit experiment the intensity produced by each one of the individual slits is \(I_0\). The distance between two slits is \(2\,\text{mm}\). The distance of screen from slits is \(10\,\text{m}\). The wavelength of light is \(6000\,\text{\AA}\). The intensity of light on the screen in front of one of the slits is ________.
In the Young's double slit experiment the intensity produced by each one of the individual slits is \(I_0\). The distance between two slits is \(2\,\text{mm}\). The distance of screen from slits is \(10\,\text{m}\). The wavelength of light is \(6000\,\text{\AA}\). The intensity of light on the screen in front of one of the slits is ________.
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Maximum or minimum interference occurs only at points equidistant from both slits.
Updated On: Feb 5, 2026
- \( I_0 \)
- \( 2I_0 \)
- \( \dfrac{I_0}{2} \)
- \( 4I_0 \)
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The Correct Option is A
Solution and Explanation
Step 1: Identify the point on the screen.
The point directly in front of one slit is not equidistant from both slits. Hence, interference is not necessarily constructive or destructive.
Step 2: Consider contribution of the nearer slit.
At this point, light from the nearer slit reaches the screen normally and produces intensity \(I_0\).
Step 3: Contribution of the other slit.
The contribution of the other slit is negligible due to path difference and angular separation. Therefore, it does not significantly affect intensity at this point.
Step 4: Final conclusion.
Hence, the intensity on the screen in front of one slit is equal to the intensity produced by that slit alone, i.e. \(I_0\).
The point directly in front of one slit is not equidistant from both slits. Hence, interference is not necessarily constructive or destructive.
Step 2: Consider contribution of the nearer slit.
At this point, light from the nearer slit reaches the screen normally and produces intensity \(I_0\).
Step 3: Contribution of the other slit.
The contribution of the other slit is negligible due to path difference and angular separation. Therefore, it does not significantly affect intensity at this point.
Step 4: Final conclusion.
Hence, the intensity on the screen in front of one slit is equal to the intensity produced by that slit alone, i.e. \(I_0\).
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