In the neutral or faintly alkaline medium, KMnO4 oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from
- (+7 to +4)
- (+6 to +4)
- (+7 to +3)
- (+6 to +5)
The Correct Option is A
Solution and Explanation
In the given reaction, KMnO4 acts as an oxidizing agent, and iodide (I-) is oxidized to iodate (IO3-). In an alkaline or neutral medium, the balanced equation for the oxidation process is as follows:
2 KMnO4 + H2O + I- → 2 MnO2 + 2 KOH + IO3-
To determine the change in the oxidation state of manganese (Mn), let's analyze its transformation in the reaction:
- In KMnO4, Mn is in the +7 oxidation state.
- In MnO2, Mn is in the +4 oxidation state.
Thus, the change in the oxidation state of manganese is from +7 in KMnO4 to +4 in MnO2.
The correct answer to the change in oxidation state of manganese is (+7 to +4).
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Concepts Used:
Oxidation and Reduction
What is Oxidation?
Oxidation is a chemical process which can be explained by following four point of views
In terms of oxygen transfer
In terms of electron transfer
In terms of hydrogen transfer
In terms of oxidation number
Oxidation in Terms of Oxygen Transfer – Oxidation is gain of oxygen.
What is Reduction?
Reduction is a chemical process which can be explained by following four point of views
In terms of oxygen transfer
In terms of electron transfer
In terms of hydrogen transfer
In terms of oxidation number
Reduction in Terms of Oxygen Transfer – Reduction is loss of oxygen.
What is Redox Reaction?
A chemical reaction which involves transfer of electrons or change in oxidation number of atoms is called redox reaction.