Question:

In the group $G= \{0, 1,2, 3,4, 5\}$ under addition modulo $6,(2 +_6 3^{-1} +_6 4)^{-1}$=

Updated On: Apr 2, 2024
  • 0
  • 2
  • 3
  • 5
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

$\left(2+{ }_{6} 3^{-1}+{ }_{6} 4\right)^{-1}=\left(2+{ }_{6} 3+{ }_{6} 4\right)^{-1} \,\,\,\,\,\left(\because 3^{-1}=3\right)$ $=(5+64)^{-1}=(3)^{-1}$ $=3$
Was this answer helpful?
0
0

Concepts Used:

Relations and functions

A relation R from a non-empty set B is a subset of the cartesian product A × B. The subset is derived by describing a relationship between the first element and the second element of the ordered pairs in A × B.

A relation f from a set A to a set B is said to be a function if every element of set A has one and only one image in set B. In other words, no two distinct elements of B have the same pre-image.

Representation of Relation and Function

Relations and functions can be represented in different forms such as arrow representation, algebraic form, set-builder form, graphically, roster form, and tabular form. Define a function f: A = {1, 2, 3} → B = {1, 4, 9} such that f(1) = 1, f(2) = 4, f(3) = 9. Now, represent this function in different forms.

  1. Set-builder form - {(x, y): f(x) = y2, x ∈ A, y ∈ B}
  2. Roster form - {(1, 1), (2, 4), (3, 9)}
  3. Arrow Representation