Question:

In the given figure, PQRS is a parallelogram with \(PS=7\) cm, \(PT=4\) cm and \(PV=5\) cm. What is the length of \(RS\) in cm? (The diagram is representative.)

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- For any parallelogram, the product \(\text{base} \times \text{height}\) is invariant. - Perpendicular distances from the same vertex to opposite sides can be used as heights with the corresponding bases.
Updated On: Aug 26, 2025
  • \(\dfrac{20}{7}\)
  • \(\dfrac{28}{5}\)
  • \(\dfrac{9}{2}\)
  • \(\dfrac{35}{4}\)
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The Correct Option is B

Solution and Explanation

Step 1: In a parallelogram, the area is \( \text{base} \times \text{corresponding height} \). Using base \(PS\) and its perpendicular height \(PT\): \[ \text{Area}= PS \times PT = 7 \times 4 = 28 \ \text{cm}^2. \] The same area can be written using base \(RS\) and the perpendicular distance from \(P\) to \(RS\), which is \(PV\): \[ \text{Area}= RS \times PV = RS \times 5. \] Equating the areas, \[ RS \times 5 = 28 \quad \Rightarrow \quad RS=\frac{28}{5}\ \text{cm}. \]
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