Question

In the given cycle ABCDA, the heat required for an ideal monoatomic gas will be: 
 

• A. \( p_0 V_0 \)
• B. \( \frac{13}{2} p_0 V_0 \)
• C. \( \frac{11}{2} p_0 V_0 \)
• D. \( 4 p_0 V_0 \)

Hint:

For cyclic processes, heat calculation depends on specific heat at constant volume \( C_V \) and constant pressure \( C_P \).

Answer 1

The Correct Option is B

Step 1: {Heat supplied in process DA and AB}
\[ Q = n C_V (\Delta T)_{DA} + n C_P (\Delta T)_{AB} \] Step 2: {For an ideal monoatomic gas,}
\[ C_V = \frac{3}{2} R, \quad C_P = \frac{5}{2} R \] Step 3: {Substituting values}
\[ Q = \frac{3}{2} (p_0 V_0) + 5 (p_0 V_0) \] \[ = \frac{13}{2} p_0 V_0 \] Thus, the correct answer is \( \frac{13}{2} p_0 V_0 \).