In the following substitution reaction:
The given reaction involves the substitution of a bromine atom with an ethoxy group (\( {OC}_2{H}_5 \)) in the presence of sodium ethoxide (\( {C}_2{H}_5{ONa} \)). The nitro group remains unaffected during the substitution. The ethoxy group replaces the bromine atom, forming an ethoxy substituted compound. Thus, the product 'P' formed is represented by the structure:
Therefore, the correct answer is option (1).
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: