The formula governs the refraction at a spherical surface
\(\frac{μ2}{v} −\frac{ μ1}{ u} = \frac{μ2 − μ1}{ R}\)
where, \(\mu_1 = 1 \ (\text{for air}), \ \mu_2 = \frac{4}{3}, \ u = -20 \ \text{cm}, \ R = 10 \ \text{cm}\)
Substitute the values into the formula
\(\frac{4}{3v} - \frac{1}{-20} = \frac{\frac{4}{3} - 1}{10}\)
Simplifying, \(\frac{4}{3v} + \frac{1}{20} = \frac{1}{30}\)
\(\frac{4}{3v} = \frac{1}{30} - \frac{1}{20} = \frac{2 - 3}{60} = \frac{-1}{60}\)
\(v = -16 \ \text{cm}\),
This means the image is 16 cm to the left of P in air.
In the diagram given below, there are three lenses formed. Considering negligible thickness of each of them as compared to \( R_1 \) and \( R_2 \), i.e., the radii of curvature for upper and lower surfaces of the glass lens, the power of the combination is: