Question:

In the figure given below, APB is a curved surface of radius of curvature 10 cm separating air and a transparent material \((μ = \frac{4}{3} ).\) A point object O is placed in air on the principal axis of the surface 20 cm from P. The distance of the image of O from P will be _____.Radius of curvature
Fill in the blank with the correct answer from the options given below

Updated On: Mar 28, 2025
  • 16 cm left of P in air
  • 16 cm right of P in water
  • 20 cm right of P in water
  • 20 cm left of P in air
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The Correct Option is A

Solution and Explanation

The formula governs the refraction at a spherical surface

 

                                                                            \(\frac{μ2}{v} −\frac{ μ1}{ u} = \frac{μ2 − μ1}{ R}\)

                                             where, \(\mu_1 = 1 \ (\text{for air}), \ \mu_2 = \frac{4}{3}, \ u = -20 \ \text{cm}, \ R = 10 \ \text{cm}\)

Substitute the values into the formula

                                                                                       \(\frac{4}{3v} - \frac{1}{-20} = \frac{\frac{4}{3} - 1}{10}\)

                                                                                 Simplifying, \(\frac{4}{3v} + \frac{1}{20} = \frac{1}{30}\)

                                                                              \(\frac{4}{3v} = \frac{1}{30} - \frac{1}{20} = \frac{2 - 3}{60} = \frac{-1}{60}\)

                                                                                       \(v = -16 \ \text{cm}\)
This means the image is 16 cm to the left of P in air.

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