Question:
In the figure \(∠BAO 30°, ∠BCO=40°\) then \(∠AOC = ?\)
In the figure \(∠BAO 30°, ∠BCO=40°\) then \(∠AOC = ?\)
Updated On: Apr 30, 2024
- \(100°\)
- \(120°\)
- \(140°\)
- \(150°\)
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
The correct option is (C): \(140°\)
Was this answer helpful?
0
0
Top Questions on Triangles
- Sides $AB$ and $BC$ and median $AD$ of a $△ABC$ are respectively proportional to sides $PQ$ and $PR$ and median $PM$ of $△PQR$. Show that $△ABC ∼ △PQR$.
- If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then prove that the other two sides are divided in the same ratio.
- \(D\) is a point on the side \(BC\) of \(\triangle ABC\) such that \(\angle ADC = \angle BAC\). Show that:
\(AC^2 = BC \times DC\)
- Sides $AB$ and $BC$ and median $AD$ of a $△ABC$ are respectively proportional to sides $PQ$ and $PR$ and median $PM$ of $△PQR$. Show that $△ABC ∼ △PQR$.
- If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then prove that the other two sides are divided in the same ratio.
View More Questions
Questions Asked in TS POLYCET exam
- The value of \(\tan 26^\circ. \tan 64^\circ\) is
- TS POLYCET - 2023
- Trigonometry
- When white light is incident on a glass prism, the least deviated colour is
- TS POLYCET - 2023
- Wave Optics
- If 5x+py+8=0 and 10x+15y+12=0 has no solution, then p =
- TS POLYCET - 2023
- Quadratic Equations
- If \(\sec \theta = \frac{2}{\sqrt{3}}\),then \(cosθ=\)
- TS POLYCET - 2023
- Trigonometry
- In the figure, if AP and AQ are the two tangents to a circle with centre 'O' so that \(∠OQP=15°\), then \(∠QAP=\)
- TS POLYCET - 2023
- Tangent to a Circle
View More Questions