To solve this question, we need to identify the gas that is liberated when a salt containing chloride is treated with concentrated sulfuric acid. Let's examine the reaction:
When a chloride salt (e.g., NaCl) is treated with concentrated sulfuric acid (H2SO4), the following reaction occurs:
\(\text{NaCl (s) + H}_2\text{SO}_4\text{ (l) } \rightarrow \text{NaHSO}_4\text{ (s) + HCl (g)}\)
In this reaction, hydrogen chloride gas (HCl) is liberated, which is a colorless gas. This accurately matches the description in the question.
Let's examine the incorrect options:
Therefore, the correct answer is Hydrogen chloride gas.
Given below are two statements. 
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
In a practical examination, the following pedigree chart was given as a spotter for identification. The students identify the given pedigree chart as 