In the circuit shown, the end A is at potential \( V_0 \), and end B is grounded. The electric current indicated in the circuit is
- \( \frac{V_0}{R} \)
- \( \frac{2V_0}{R} \)
- \( \frac{V_0}{3R} \)
- \( \frac{V_0}{2R} \)
The Correct Option is C
Solution and Explanation
The current $i$ in the circuit is determined by the formula:
\[ i = \frac{V_0}{R_\text{eff}} \] where $R_\text{eff}$ is the effective resistance of the circuit.
For the given configuration: \[ R_\text{eff} = R + 2R = 3R \]
Top Questions on Current electricity
Two cells of emf 1V and 2V and internal resistance 2 \( \Omega \) and 1 \( \Omega \), respectively, are connected in series with an external resistance of 6 \( \Omega \). The total current in the circuit is \( I_1 \). Now the same two cells in parallel configuration are connected to the same external resistance. In this case, the total current drawn is \( I_2 \). The value of \( \left( \frac{I_1}{I_2} \right) \) is \( \frac{x}{3} \). The value of x is 1cm.
- JEE Main - 2025
- Physics
- Current electricity
- A body starts from rest and moves with an acceleration of \(2 \, \text{m/s}^2\) and comes to rest with a retardation of \(2 \, \text{m/s}^2\). Find the distance travelled?
- KEAM - 2025
- Physics
- Current electricity
- Energy dissipated per unit time by a wire of resistance \(2R\) connected to a 2V battery.
- KEAM - 2025
- Physics
- Current electricity
Current passing through a wire as function of time is given as $I(t)=0.02 \mathrm{t}+0.01 \mathrm{~A}$. The charge that will flow through the wire from $t=1 \mathrm{~s}$ to $\mathrm{t}=2 \mathrm{~s}$ is:
- JEE Main - 2025
- Physics
- Current electricity
In the figure shown below, a resistance of 150.4 $ \Omega $ is connected in series to an ammeter A of resistance 240 $ \Omega $. A shunt resistance of 10 $ \Omega $ is connected in parallel with the ammeter. The reading of the ammeter is ______ mA.
- JEE Main - 2025
- Physics
- Current electricity
Questions Asked in KCET exam
The graph between variation of resistance of a wire as a function of its diameter keeping other parameters like length and temperature constant is
- KCET - 2025
- Resistance
- If \[ y = \frac{\cos x}{1 + \sin x} \] then:
- KCET - 2025
- Differentiability
- If \(A\) is a square matrix such that \(A^2 = A\), then \((I - A)^3\) is:
- KCET - 2025
- Matrices
While determining the coefficient of viscosity of the given liquid, a spherical steel ball sinks by a distance \( x = 0.8 \, \text{m} \). The radius of the ball is \( 2.5 \times 10^{-3} \, \text{m} \). The time taken by the ball to sink in three trials are tabulated as shown:
- KCET - 2025
- Dimensional Analysis
- General solution of the differential equation \[ \frac{dy}{dx} + y \tan x = \sec x \quad \text{is:} \]
- KCET - 2025
- Differential equations