
The current $i$ in the circuit is determined by the formula:
\[ i = \frac{V_0}{R_\text{eff}} \] where $R_\text{eff}$ is the effective resistance of the circuit.
For the given configuration: \[ R_\text{eff} = R + 2R = 3R \]



The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: 