Question:

In series LCR circuit, the capacitance is changed from C to 4C. To keep the resonance frequency unchanged, the new inductance should be :

Updated On: Nov 14, 2024
  • reduced by\(\frac{1}{4}L\)
  • increased by 2L
  • reduced by\(\frac{3}{4}L\)
  • increased by 4L
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The Correct Option is C

Solution and Explanation

To keep the resonance frequency \(\omega\) unchanged, we know:

\[ \omega' = \omega = \frac{1}{\sqrt{L'C'}} \]

Given:

\[ L'C' = LC \]

Substituting \(C' = 4C\) into the equation:

\[ L' \cdot (4C) = LC \implies L' = \frac{L}{4} \]

Thus, the inductance must be decreased by:

\[ L - L' = L - \frac{L}{4} = \frac{3L}{4} \]

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