Question:
A LCR circuit is at resonance for a capacitor C, inductance L and resistance R. Now the value of resistance is halved keeping all other parameters same. The current amplitude at resonance will be now:
A LCR circuit is at resonance for a capacitor C, inductance L and resistance R. Now the value of resistance is halved keeping all other parameters same. The current amplitude at resonance will be now:
Updated On: Aug 1, 2025
- Zero
- double
- same
- halved
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The Correct Option is B
Solution and Explanation
At resonance, impedance is given by:
\[ Z = R. \]
The current in the circuit is:
\[ I = \frac{V}{R}. \]
When the resistance \(R\) is halved:
\[ R \to \frac{R}{2}, \quad I \to 2I. \]
Thus, the current amplitude becomes double.
Final Answer: Double.
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