In the Reimer-Tiemann reaction, phenol reacts with chloroform (CHCl$_3$) and aqueous sodium hydroxide (NaOH) to form salicylaldehyde via the following mechanism:
Phenol undergoes ortho-substitution due to the electrophilic attack of dichlorocarbene (:CCl$_2$), generated in situ from CHCl$_3$ and NaOH.
The intermediate formed is the sodium salt of dichlorophenol.
On further hydrolysis and protonation, salicylaldehyde is obtained.
The reaction proceeds as:
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).