Given:
Power = 100 KW
Voltage = 125 V
ECE of chlorine Z = 0.367 x 10-6 kg/C
Power P = Vi
100 = 125 x i
i = \(\frac {100}{125}\)
i = 0.8 A
We know that first law of electrolysis
m = Zit
m = 0.367× 10−6 × 0.8 × 60
m = 17.616 × 10−6 kg
m = 17.616 × 10−6 x 106 mg
m = 17.6 mg
So, the correct option is (A): 17.6 mg


A battery of emf \( E \) and internal resistance \( r \) is connected to a rheostat. When a current of 2A is drawn from the battery, the potential difference across the rheostat is 5V. The potential difference becomes 4V when a current of 4A is drawn from the battery. Calculate the value of \( E \) and \( r \).
Electrolysis is the process by which an element is decomposed and undergoes some chemical change under the influence of any electric current. The first-ever electrolysis was executed out by Sir Humphrey Davey in the year 1808. Electrolysis can occur in both Galvanic cells and Electrolytic cells.
Read More: Products of Electrolysis