Given:
Power = 100 KW
Voltage = 125 V
ECE of chlorine Z = 0.367 x 10-6 kg/C
Power P = Vi
100 = 125 x i
i = \(\frac {100}{125}\)
i = 0.8 A
We know that first law of electrolysis
m = Zit
m = 0.367× 10−6 × 0.8 × 60
m = 17.616 × 10−6 kg
m = 17.616 × 10−6 x 106 mg
m = 17.6 mg
So, the correct option is (A): 17.6 mg
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec:
Electrolysis is the process by which an element is decomposed and undergoes some chemical change under the influence of any electric current. The first-ever electrolysis was executed out by Sir Humphrey Davey in the year 1808. Electrolysis can occur in both Galvanic cells and Electrolytic cells.
Read More: Products of Electrolysis