Given:
Power = 100 KW
Voltage = 125 V
ECE of chlorine Z = 0.367 x 10-6 kg/C
Power P = Vi
100 = 125 x i
i = \(\frac {100}{125}\)
i = 0.8 A
We know that first law of electrolysis
m = Zit
m = 0.367× 10−6 × 0.8 × 60
m = 17.616 × 10−6 kg
m = 17.616 × 10−6 x 106 mg
m = 17.6 mg
So, the correct option is (A): 17.6 mg
Two cells of emf 1V and 2V and internal resistance 2 \( \Omega \) and 1 \( \Omega \), respectively, are connected in series with an external resistance of 6 \( \Omega \). The total current in the circuit is \( I_1 \). Now the same two cells in parallel configuration are connected to the same external resistance. In this case, the total current drawn is \( I_2 \). The value of \( \left( \frac{I_1}{I_2} \right) \) is \( \frac{x}{3} \). The value of x is 1cm.
In the figure shown below, a resistance of 150.4 $ \Omega $ is connected in series to an ammeter A of resistance 240 $ \Omega $. A shunt resistance of 10 $ \Omega $ is connected in parallel with the ammeter. The reading of the ammeter is ______ mA.
The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.
Electrolysis is the process by which an element is decomposed and undergoes some chemical change under the influence of any electric current. The first-ever electrolysis was executed out by Sir Humphrey Davey in the year 1808. Electrolysis can occur in both Galvanic cells and Electrolytic cells.
Read More: Products of Electrolysis