Question

In gas phase, \( \text{H-O-O-H} \) bond angle in \( \text{H}_2\text{O}_2 \) is

• A. 111.5°
• B. 94.8°
• C. 98.4°
• D. 147.5°

Hint:

In bent molecules, the bond angle is often smaller than the ideal tetrahedral angle due to lone pair repulsion.

Answer 1

The Correct Option is B

Step 1: Understanding the molecular geometry.
In \( \text{H}_2\text{O}_2 \), the molecule adopts a bent shape due to lone pair repulsion, and the bond angle is less than the ideal tetrahedral angle of 109.5°.

Step 2: Analyzing the options.
(A) 111.5°: This is incorrect, as the bond angle in \( \text{H}_2\text{O}_2 \) is smaller.
(B) 94.8°: Correct — The \( \text{H-O-O-H} \) bond angle in \( \text{H}_2\text{O}_2 \) is 94.8°, which is a typical bond angle for bent molecules with lone pair repulsions.
(C) 98.4°: This is incorrect. The bond angle is closer to 94.8°.
(D) 147.5°: This is much too large for a bent structure.

Step 3: Conclusion.
The correct answer is (B) 94.8°.