Statement-I: Sucrose is dextrorotatory upon hydrolysis it becomes laevorotatory. Statement-II: Sucrose on hydrolysis gives glucose and fructose such that the levorotation of glucose is more than dexrotation of fructose.
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In hydrolysis reactions of sucrose, the optical rotation changes due to the different rotations of glucose and fructose. The overall rotation depends on their relative strengths.
Step 1: Analyzing Statement-I.
Sucrose is a disaccharide composed of glucose and fructose. It is dextrorotatory (optically active in the clockwise direction). Upon hydrolysis with HCl, sucrose is broken down into glucose and fructose. The hydrolyzed products are laevorotatory. This is because the levorotation of the glucose is higher than the dexrotation of the fructose, leading to an overall negative optical rotation. Thus, Statement-I is true.
Step 2: Analyzing Statement-II.
While it is true that glucose and fructose are produced upon hydrolysis of sucrose, Statement-II claims that the levorotation of glucose is more than the dexrotation of fructose. This is incorrect. The dexrotation of glucose is actually greater than the levorotation of fructose. Therefore, Statement-II is false.
Step 3: Conclusion.
The correct conclusion is that Statement-I is true and Statement-II is false. Hence, the correct answer is (1).
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