The reduction of permanganate anion (MnO$_4^-$) in alkaline medium involves the following process:
\[ \text{MnO}_4^- \, (\text{oxidation state of Mn} = +7) \rightarrow \text{Mn}^{4+} \, (\text{oxidation state of Mn} = +4) \] The reduction from Mn$^{7+}$ to Mn$^{4+}$ involves the gain of 3 electrons, as the change in oxidation number is from +7 to +4.
Therefore, the reduction of permanganate anion involves the gain of 3 electrons.
Given below are two statements:
Statement I: The conversion proceeds well in a less polar medium. \[ {CH}_3{CH}_2{CH}_2{CH}_2{Cl} \xrightarrow{{HO}^-} {CH}_3{CH}_2{CH}_2{CH}_2{OH} + {Cl}^- \] Statement II: The conversion proceeds well in a more polar medium. \[ {CH}_3{CH}_2{CH}_2{CH}_2{Cl} \xrightarrow{{R}_3{N}} {CH}_3{CH}_2{CH}_2{CH}_2{NH}_2 + {Cl}^- \] In the light of the above statements, choose the correct answer from the options given below:
Match List-I with List-II.
Choose the correct answer from the options given below :