Question

In acidic medium, \( K_2Cr_2O_7 \) shows oxidizing action as represented in the half-reaction: \(Cr_2O_7^{2-} + XH^+ + Ye^- \rightarrow 2A + ZH_2O\)
\( X \), \( Y \), \( Z \), and \( A \) are respectively:

• A. 8, 6, 4, and \( Cr_2O_3 \)
• B. 14, 7, 6, and \( Cr^{3+} \)
• C. 8, 4, 6, and \( Cr_2O_3 \)
• D. 14, 6, 7, and \( Cr^{3+} \)

Answer 1

The Correct Option is D

The balanced reaction is:

\[ \text{Cr}_2\text{O}_7^{2-} + 14\text{H}^+ + 6e^- \rightarrow 2\text{Cr}^{3+} + 7\text{H}_2\text{O} \]

From the reaction, we have:

\[ X = 14, \quad Y = 6, \quad Z = 7, \quad A = \text{Cr}^{3+} \]