Question:

In a resistive circuit, the power dissipated by a resistor \( R \) when a current \( I \) flows through it is given by \( P = I^2 R \). What happens to the power when the current is doubled?

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In a resistive circuit, power is proportional to the square of the current. Doubling the current results in a fourfold increase in power dissipation.
Updated On: Mar 18, 2025
  • It quadruples
  • It doubles
  • It remains the same
  • It is halved
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The Correct Option is A

Solution and Explanation

The power dissipated in a resistor is given by \( P = I^2 R \). If the current is doubled, i.e., \( I \rightarrow 2I \), the power becomes: \[ P' = (2I)^2 R = 4I^2 R. \] Thus, the power quadruples when the current is doubled.
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