In a resistive circuit, the power dissipated by a resistor \( R \) when a current \( I \) flows through it is given by \( P = I^2 R \). What happens to the power when the current is doubled?
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In a resistive circuit, power is proportional to the square of the current. Doubling the current results in a fourfold increase in power dissipation.
The power dissipated in a resistor is given by \( P = I^2 R \). If the current is doubled, i.e., \( I \rightarrow 2I \), the power becomes:
\[
P' = (2I)^2 R = 4I^2 R.
\]
Thus, the power quadruples when the current is doubled.