Question

In a hydraulic lift, the surface area of the input piston is 6 cm² and that of the output piston is 1500 cm². If 100 N force is applied to the input piston to raise the output piston by 20 cm, then the work done is _________  kJ.

Hint:

In hydraulic systems, the work done is the same on both pistons. Use the formula \( W = F \times d \) to calculate work, remembering to convert units appropriately.

Answer 1

The work done on the input piston is the force applied multiplied by the displacement: \[ W_{{input}} = F \times d = 100 \times 20 = 2000 \, {N cm} \] To convert this to Joules, we divide by 100 (since 1 J = 100 N·cm): \[ W_{{input}} = 2000 \, {N cm} / 100 = 20 \, {J} = 0.01 \, {kJ} \] Thus, the correct answer is \( 0.01 \, {kJ} \).