Question:

In a class A of 25 students, 20 passed with 60% or more marks; in another class B of 30 students, 24 passed with 60% or more marks. In which class was a greater fraction of students getting with 60% or more marks?

Updated On: Dec 20, 2023
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Solution and Explanation

The total students in class AA = 2525
The students who passed with 60%60\% or more = 2020.
The fraction of students who passed with 60%60\% or more = 2025=45\frac{20}{25} = \frac{4}{5}

The total students in class BB = 3030
The students passed with 60%60\% or more = 2424
The fraction of students who passed with 60%60\% or more = 2430=45\frac{24}{30} = \frac{4}{5}

By evaluating both fractions, we find 45=45\frac{4}{5} = \frac{4}{5}.

The identical fractions, 45\frac{4}{5} in both cases, solidify the fact that both classes share the same proportion of high scorers.

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