The total students in class \(A\) = \(25\)
The students who passed with \(60\%\) or more = \(20\).
The fraction of students who passed with \(60\%\) or more = \(\frac{20}{25} = \frac{4}{5}\)
The total students in class \(B\) = \(30\)
The students passed with \(60\%\) or more = \(24\)
The fraction of students who passed with \(60\%\) or more = \(\frac{24}{30} = \frac{4}{5}\)
By evaluating both fractions, we find \(\frac{4}{5} = \frac{4}{5}\).
The identical fractions, \(\frac{4}{5}\) in both cases, solidify the fact that both classes share the same proportion of high scorers.
Complete the drawing shown in Fig. 9.14 to indicate where the free ends of the two wires should be joined to make the bulb glow