Question:

In a class A of 25 students, 20 passed with 60% or more marks; in another class B of 30 students, 24 passed with 60% or more marks. In which class was a greater fraction of students getting with 60% or more marks?

Updated On: Dec 20, 2023
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Solution and Explanation

The total students in class \(A\) = \(25\)
The students who passed with \(60\%\) or more = \(20\).
The fraction of students who passed with \(60\%\) or more = \(\frac{20}{25} = \frac{4}{5}\)

The total students in class \(B\) = \(30\)
The students passed with \(60\%\) or more = \(24\)
The fraction of students who passed with \(60\%\) or more = \(\frac{24}{30} = \frac{4}{5}\)

By evaluating both fractions, we find \(\frac{4}{5} = \frac{4}{5}\).

The identical fractions, \(\frac{4}{5}\) in both cases, solidify the fact that both classes share the same proportion of high scorers.

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