(a) \(\frac{1}{6} [ < ]\frac{1}{3}\) - The numerators of two given fractions are the same. So, the fraction that has the lesser denominator is the largest.
(b) \(\frac{3}{4} [ > ]\frac{ 2}{6}\) - Cross multiplying the denominators and the numerators, we have 3/4 =9/12 and 2/6=4/12. Here, for 9/12 and 4/12, 9 >. The denominators of the two fractions are the same. So, the fraction that has the greater numerator is the largest.
(c) \(\frac{2}{3} [ > ] \frac{2}{4}\) - The numerators of two given fractions are the same. So, the fraction that has the lesser denominator is the largest.
(d) \(\frac{6}{6} [ = ] \frac{3}{3}\) - \(\frac{6}{6}\) and \(\frac{3}{3}\) can be both simplified to \(1\) and hence they are equal.
(e) \(\frac{5}{6} [ < ] \frac{5}{5}\) - The numerators of two given fractions are the same. So, the fraction that has the lesser denominator is the largest.
Five more such problems are:
(a) \(\frac{1}{7} [<] \frac{1}{4}\)
(b) \(\frac{5}{8} [>] \frac{4}{12}\)
(c) \(\frac{4}{6} [>] \frac{4}{8}\)
(d) \(\frac{4}{4} (=)\frac{ 2}{2}\)
(e) \(\frac{10}{12} [<] \frac{10}{10}\)
Complete the drawing shown in Fig. 9.14 to indicate where the free ends of the two wires should be joined to make the bulb glow