To calculate the percentage of H₂O in the product, we use the following formula:
\[
\text{Percentage of H₂O in product} = \frac{\text{Weight of H₂O in product}}{\text{Total weight of product}} \times 100
\]
(1) The total weight of reactants entering the vessel is:
\[
\text{Total reactant weight} = 70 \, \text{Kg of H₂O} + 10 \, \text{Kg of NaOH} = 80 \, \text{Kg}
\]
(2) If 100 Kg of product leaves the vessel, we assume that all 70 Kg of H₂O is present in the product. Therefore, the weight of H₂O in the product is 70 Kg.
(3) The percentage of H₂O in the product is:
\[
\text{Percentage of H₂O} = \frac{70}{100} \times 100 = 70\%
\]
Conclusion:
The correct answer is Option 3: 70\% as it represents the percentage of H₂O in the product.