In a batch process, 70 Kg of H₂O and 10 Kg of NaOH and some other reactants enters the vessel. If 100 Kg of the product leaves the vessel, what is the percentage of H₂O in the product?
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In batch processes, the percentage of each component in the product can be calculated by dividing the mass of the component by the total mass of the product.
To calculate the percentage of H₂O in the product, we use the following formula:
\[
\text{Percentage of H₂O in product} = \frac{\text{Weight of H₂O in product}}{\text{Total weight of product}} \times 100
\]
(1) The total weight of reactants entering the vessel is:
\[
\text{Total reactant weight} = 70 \, \text{Kg of H₂O} + 10 \, \text{Kg of NaOH} = 80 \, \text{Kg}
\]
(2) If 100 Kg of product leaves the vessel, we assume that all 70 Kg of H₂O is present in the product. Therefore, the weight of H₂O in the product is 70 Kg.
(3) The percentage of H₂O in the product is:
\[
\text{Percentage of H₂O} = \frac{70}{100} \times 100 = 70\%
\]
Conclusion:
The correct answer is Option 3: 70\% as it represents the percentage of H₂O in the product.