can be subjected to Wolff-Kishner reduction to give
into 
The Wolff-Kishner reduction converts a carbonyl group (\( C=O \)) into a methylene group (\( CH_2 \)). The assertion states that 2-chloropropanal (\( \text{CH}_3\text{CHClCHO} \)) can undergo Wolff-Kishner reduction to form 2-chloropropane
.
This assertion is false, because the Wolff-Kishner reduction would reduce the aldehyde group (\( C=O \)) to a methylene group (\( CH_2 \)), but it cannot alter or affect the chlorine substituent.
The reaction proceeds as follows:

The reason states that the Wolff-Kishner reduction is used to convert \( C=O \) into \( CH_2 \). This is true and represents the principle behind the Wolff-Kishner reduction, where hydrazine (\( \text{NH}_2\text{NH}_2 \)) reacts with the carbonyl compound in the presence of a strong base like \( \text{KOH} \).
A is false but R is true.




If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
The output of the circuit is low (zero) for:

(A) \( X = 0, Y = 0 \)
(B) \( X = 0, Y = 1 \)
(C) \( X = 1, Y = 0 \)
(D) \( X = 1, Y = 1 \)
Choose the correct answer from the options given below:
The metal ions that have the calculated spin only magnetic moment value of 4.9 B.M. are
A. $ Cr^{2+} $
B. $ Fe^{2+} $
C. $ Fe^{3+} $
D. $ Co^{2+} $
E. $ Mn^{2+} $
Choose the correct answer from the options given below
Which of the following circuits has the same output as that of the given circuit?
