We are given \(\frac{z}{i} = 11 - 13i\), and we need to find \(z + \bar{z}\).
First, multiply both sides of the equation by \(i\) to find \(z\):
\(z = i(11 - 13i)\)
Now, distribute \(i\):
\(z = 11i - 13i^2\)
Since \(i^2 = -1\), we have:
\(z = 11i + 13\)
Now, we find \(\bar{z}\), the conjugate of \(z\):
\(\bar{z} = 13 - 11i\)
Now, calculate \(z + \bar{z}\):
\(z + \bar{z} = (13 + 11i) + (13 - 11i) = 13 + 13 = 26\)
The answer is 26.
Let \( z \) satisfy \( |z| = 1, \ z = 1 - \overline{z} \text{ and } \operatorname{Im}(z)>0 \)
Then consider:
Statement-I: \( z \) is a real number
Statement-II: Principal argument of \( z \) is \( \dfrac{\pi}{3} \)
Then:
If \( z \) and \( \omega \) are two non-zero complex numbers such that \( |z\omega| = 1 \) and
\[ \arg(z) - \arg(\omega) = \frac{\pi}{2}, \]
Then the value of \( \overline{z\omega} \) is: