We are given \(\frac{z}{i} = 11 - 13i\), and we need to find \(z + \bar{z}\).
First, multiply both sides of the equation by \(i\) to find \(z\):
\(z = i(11 - 13i)\)
Now, distribute \(i\):
\(z = 11i - 13i^2\)
Since \(i^2 = -1\), we have:
\(z = 11i + 13\)
Now, we find \(\bar{z}\), the conjugate of \(z\):
\(\bar{z} = 13 - 11i\)
Now, calculate \(z + \bar{z}\):
\(z + \bar{z} = (13 + 11i) + (13 - 11i) = 13 + 13 = 26\)
The answer is 26.
If \( z \) is a complex number and \( k \in \mathbb{R} \), such that \( |z| = 1 \), \[ \frac{2 + k^2 z}{k + \overline{z}} = kz, \] then the maximum distance from \( k + i k^2 \) to the circle \( |z - (1 + 2i)| = 1 \) is: