We are given that \( z^4 = 7 - 5i \). First, recall that the conjugate of \( z \), denoted \( \overline{z} \), satisfies: \[ \overline{z^4} = (\overline{z})^4 \] Taking the conjugate of both sides of \( z^4 = 7 - 5i \), we get: \[ \overline{z^4} = \overline{7 - 5i} = 7 + 5i \] Thus, we have: \[ (\overline{z})^4 = 7 + 5i \] Now, the imaginary part of \( (\overline{z})^4 \) is the coefficient of \( i \), which is \( 5 \). Therefore: \[ \text{Im} \left( (\overline{z})^4 \right) = 5 \]
The correct option is (A) : \(5\)
We are given that \(z^4 = 7 - 5i\). We want to find the imaginary part of \((\bar{z})^4\).
We know that \((\bar{z})^4 = \overline{z^4}\).
Therefore, \((\bar{z})^4 = \overline{7 - 5i} = 7 + 5i\).
The imaginary part of \((\bar{z})^4\) is the imaginary part of \(7 + 5i\), which is 5.
Therefore, Im((\(\bar{z}\))^4) is equal to 5.
Let \(S=\left\{ z\in\mathbb{C}:\left|\frac{z-6i}{z-2i}\right|=1 \text{ and } \left|\frac{z-8+2i}{z+2i}\right|=\frac{3}{5} \right\}.\)
Then $\sum_{z\in S}|z|^2$ is equal to