If x = log (y +√y2 + 1 ) then y =
tanh x
coth x
sinh x
cosh x
The correct option is: (C) sinh x.
y=sinh(x), let's start by solving the equation x=log(y+y2+1) for y.
Given equation: x=log(y+y2+1)
First, let's eliminate the logarithm by exponentiating both sides with base 10: 10x=y+y2+1
Now, isolate the radical term on one side: 10x−y=y2+1
Square both sides of the equation to eliminate the square root: (10x−y)2=y2+1
Expand the left-hand side: 102x−2xy+y2=y2+1
Now, simplify the equation: 102x−2xy=1
Isolate y on one side: 2xy=102x−1 y=2x102x−1
Now, we'll express sinh(x) in terms of exponential functions: 2sinh(x)=2ex−e−x
Comparing this expression with y=2x102x−1, we notice a similarity if we substitute ex for 10x.
Therefore, we have: y=2xe2x−1
Since y=2xe2x−1 and sinh(x)=2ex−e−x are equivalent expressions, we can conclude that y=sinh(x).
Hence, the answer is justified: y=sinh(x).
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