Question:

If x+iy=1(1+cosθ)+isinθx+iy=\dfrac{1}{(1+cosθ)+isinθ},then the value of x2+1x^2+1 is ?

Updated On: May 29, 2024
  • 74\dfrac{7}{4}

  • 134\dfrac{13}{4}

  • 14\dfrac{1}{4}

  • 94\dfrac{9}{4}

  • 54\dfrac{5}{4}

Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is

Solution and Explanation

Given that:

 x+iy=1/(1+cosθ)+isinθx+iy=1/(1+cosθ)+isinθ

=11+2cos2(θ/2)+i.2sin(θ/2).cos(θ/2)=\dfrac{1}{1+2cos^2(θ/2)+i.2sin(θ/2).cos(θ/2)}

=11+2cos2(θ/2).1ei.(θ/2)=\dfrac{1}{1+2cos^2(θ/2)}.\dfrac{1}{e^{i.(θ/2)}}

=11+2cos2(θ/2).ei.(θ/2)=\dfrac{1}{1+2cos^2(θ/2)}.e^{-i.(θ/2)}

=11+2cos2(θ/2).(cos(θ/2)isin(θ/2))=\dfrac{1}{1+2cos^2(θ/2)}.(cos(θ/2)-isin(θ/2))

=12itan(θ/2)=\dfrac{1}{2}-itan(θ/2)

Hence, now we can write that  x=12x=\dfrac{1}{2}

So, x2+1=(12)2+1=54x^2+1=(\dfrac{1}{2})^2+1=\dfrac{5}{4} (_Ans.)

Was this answer helpful?
0
0

Top Questions on complex numbers

View More Questions

Questions Asked in KEAM exam

View More Questions

Concepts Used:

Complex Number

A Complex Number is written in the form

a + ib

where,

  • “a” is a real number
  • “b” is an imaginary number

The Complex Number consists of a symbol “i” which satisfies the condition i^2 = −1. Complex Numbers are mentioned as the extension of one-dimensional number lines. In a complex plane, a Complex Number indicated as a + bi is usually represented in the form of the point (a, b). We have to pay attention that a Complex Number with absolutely no real part, such as – i, -5i, etc, is called purely imaginary. Also, a Complex Number with perfectly no imaginary part is known as a real number.