We need to find the minimum value of \(\frac{2x-y}{x}\) The value of (2x – y) will be minimum when y is maximum. Also, we cannot assume ‘x’ to be negative because in that case the whole expression will become positive. ‘x’ cannot be 0. So, we can see that the minimum value of \(\frac{2x-y}{x}\) will be at x = 1 and y = 9. Required answer = \(\frac{2x-y}{x}=\frac{2-9}{1}=-7\) So, the correct option is (A): -7