Step 1: Understand the properties of similar triangles.
If \( \triangle ODC \sim \triangle OBA \), then their corresponding angles are equal. This implies:
\[
\angle DOC = \angle BOA
\]
\[
\angle ODC = \angle OBA
\]
\[
\angle OCD = \angle OAB
\]
Step 2: Use the property of vertically opposite angles.
From the given diagram, \( \angle BOC \) and \( \angle AOD \) are vertically opposite angles. Therefore,
\[
\angle AOD = \angle BOC = 125^\circ
\]
Step 3: Angles on a straight line.
The angles \( \angle BOC \) and \( \angle DOC \) are adjacent angles on a straight line (assuming \( D, O, B \) are collinear or \( C, O, A \) are collinear, which seems to be the case from the diagram). Therefore, their sum is \( 180^\circ \):
\[
\angle BOC + \angle DOC = 180^\circ
\]
Step 4: Solve for \( \angle DOC \).
We are given \( \angle BOC = 125^\circ \). Substituting this value into the equation from Step 3:
\[
125^\circ + \angle DOC = 180^\circ
\]
\[
\angle DOC = 180^\circ - 125^\circ
\]
\[
\angle DOC = 55^\circ
\]