Question:

If $\triangle ABC \sim \triangle PQR$ and $\dfrac{A(\triangle ABC)}{A(\triangle PQR)} = \dfrac{16}{25}$, then find $AB : PQ$.

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For similar triangles, remember that the ratio of their areas equals the square of the ratio of their corresponding sides.
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Solution and Explanation

Step 1: Recall the property of similar triangles.
If two triangles are similar, then the ratio of their areas is equal to the square of the ratio of their corresponding sides. That is,
\[ \dfrac{A(\triangle ABC)}{A(\triangle PQR)} = \left(\dfrac{AB}{PQ}\right)^2 \]
Step 2: Substitute the given values.
\[ \dfrac{16}{25} = \left(\dfrac{AB}{PQ}\right)^2 \]
Step 3: Take the square root on both sides.
\[ \dfrac{AB}{PQ} = \dfrac{4}{5} \]
Step 4: Conclusion.
Hence, the ratio of the corresponding sides is:
\[ AB : PQ = 4 : 5 \]
Correct Answer: $AB : PQ = 4 : 5$
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