Question:

If \( \triangle ABC \sim \triangle PQR \) and \( AB : PQ = 2 : 3 \), then find the value of \( \frac{A(\triangle ABC)}{A(\triangle PQR)} \):

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For similar triangles, the area ratio is the square of the ratio of corresponding sides.
  • \( \frac{2}{3} \)
  • \( \frac{4}{9} \)
  • \( \frac{8}{27} \)
  • \( \frac{9}{4} \)
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The Correct Option is B

Solution and Explanation

Step 1: For two similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides: \[ \frac{A(\triangle ABC)}{A(\triangle PQR)} = \left(\frac{AB}{PQ}\right)^2. \] Step 2: Substituting \( AB : PQ = 2 : 3 \): \[ \frac{A(\triangle ABC)}{A(\triangle PQR)} = \left(\frac{2}{3}\right)^2 = \frac{4}{9}. \]
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