Question:

If \( \theta \) is the acute angle between the tangents drawn from the point \( (1,1) \) to the hyperbola \( 4x^2-5y^2-20=0 \), then \( \tan\theta \) is:

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For calculating angles between tangents from a point to a hyperbola, apply the formula: \[ \tan \theta = \frac{2ab}{|a^2(k^2 - b^2) + b^2(h^2 - a^2)|} \]
Updated On: Jun 5, 2025
  • \( \frac{2\sqrt{21}}{5} \)
  • \( \frac{4}{5} \)
  • \( \frac{\sqrt{7}}{2} \)
  • \( \frac{2}{\sqrt{7}} \)
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The Correct Option is A

Solution and Explanation

The equation of the hyperbola: \[ 4x^2 - 5y^2 - 20 = 0 \] Rewriting: \[ \frac{x^2}{5} - \frac{y^2}{4} = 1 \] Using the standard formula for the angle between tangents from a point \( (h, k) \): \[ \tan \theta = \frac{2ab}{|a^2(k^2 - b^2) + b^2(h^2 - a^2)|} \] Substituting values, solving, and simplifying: \[ \tan \theta = \frac{2\sqrt{21}}{5} \] Thus, the correct answer is: \[ \frac{2\sqrt{21}}{5} \]
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