If \( \theta \) is the acute angle between the tangents drawn from the point \( (1,1) \) to the hyperbola \( 4x^2-5y^2-20=0 \), then \( \tan\theta \) is:
Show Hint
For calculating angles between tangents from a point to a hyperbola, apply the formula:
\[
\tan \theta = \frac{2ab}{|a^2(k^2 - b^2) + b^2(h^2 - a^2)|}
\]
The equation of the hyperbola:
\[
4x^2 - 5y^2 - 20 = 0
\]
Rewriting:
\[
\frac{x^2}{5} - \frac{y^2}{4} = 1
\]
Using the standard formula for the angle between tangents from a point \( (h, k) \):
\[
\tan \theta = \frac{2ab}{|a^2(k^2 - b^2) + b^2(h^2 - a^2)|}
\]
Substituting values, solving, and simplifying:
\[
\tan \theta = \frac{2\sqrt{21}}{5}
\]
Thus, the correct answer is:
\[
\frac{2\sqrt{21}}{5}
\]