A common definition for the quality factor \( Q \) around a resonance \( f_0 \) is \[ Q = \frac{f_0}{f_2 - f_1}, \] where \( f_1 \) and \( f_2 \) are the half-power (or \(-3 \, \text{dB}\)) frequencies. Here: \[ f_0 = 300 \, \text{Hz}, \quad f_1 = 150 \, \text{Hz}, \quad f_2 = 450 \, \text{Hz}. \] Thus, \[ f_2 - f_1 = 450 \, \text{Hz} - 150 \, \text{Hz} = 300 \, \text{Hz}, \quad \Rightarrow \quad Q = \frac{f_0}{f_2 - f_1} = \frac{300}{300} = 1.0. \] Hence the quality factor is \fbox{1.0}.
Europium (Eu) resembles Calcium (Ca) in the following ways:
(A). Both are diamagnetic
(B). Insolubility of their sulphates and carbonates in water
(C). Solubility of these metals in liquid NH3
(D). Insolubility of their dichlorides in strong HCI
Choose the correct answer from the options given below: