If the galvanometer G does not show any deflection in the circuit shown, the value of R is given by:
Show Hint
Applying Kirchhoff's law in the circuit.
400Ω
200Ω
50Ω
100Ω
The Correct Option is D
Solution and Explanation
The correct option is (D): 100Ω
Applying Kirchhoff's law for the whole circuit:
400i=10−2
⇒ \(i=\frac{8}{400}=\frac{1}{50}\)
when the galvanometer shows zero deflection then no current flow through it.
now for loop (first box) : 400i+Ri=10
⇒ \(i=\frac{10}{(R+400)}\)
substituting the value of i,
\(\frac{1}{50}=\frac{10}{(R+400)}\)
or R+400=500
⇒R = 100Ω
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Concepts Used:
Current Electricity
Current electricity is defined as the flow of electrons from one section of the circuit to another.
Types of Current Electricity
There are two types of current electricity as follows:
Direct Current
The current electricity whose direction remains the same is known as direct current. Direct current is defined by the constant flow of electrons from a region of high electron density to a region of low electron density. DC is used in many household appliances and applications that involve a battery.
Alternating Current
The current electricity that is bidirectional and keeps changing the direction of the charge flow is known as alternating current. The bi-directionality is caused by a sinusoidally varying current and voltage that reverses directions, creating a periodic back-and-forth motion for the current. The electrical outlets at our homes and industries are supplied with alternating current.