To solve the problem, we need to find the value of \( a \) such that the quadratic equation \( ax^2 - 8x + 4 = 0 \) has equal roots.
1. Understanding the Condition for Equal Roots:
For a quadratic equation \( ax^2 + bx + c = 0 \), the roots are equal if the discriminant is zero:
\( D = b^2 - 4ac = 0 \)
2. Identify the Coefficients:
Given equation: \( ax^2 - 8x + 4 = 0 \)
Here, \( a = a \), \( b = -8 \), and \( c = 4 \)
3. Apply the Discriminant Condition:
\[
(-8)^2 - 4a(4) = 0 \Rightarrow 64 - 16a = 0
\]
4. Solve for \( a \):
\[
64 = 16a \Rightarrow a = \frac{64}{16} = 4
\]
Final Answer:
The value of \( a \) is \( 4 \) for the equation to have equal roots.
Match List I with List II :
| List I (Quadratic equations) | List II (Roots) |
|---|---|
| (A) \(12x^2 - 7x + 1 = 0\) | (I) \((-13, -4)\) |
| (B) \(20x^2 - 9x + 1 = 0\) | (II) \(\left(\frac{1}{3}, \frac{1}{4}\right)\) |
| (C) \(x^2 + 17x + 52 = 0\) | (III) \((-4, -\frac{3}{2})\) |
| (D) \(2x^2 + 11x + 12 = 0\) | (IV) \(\left(\frac{1}{5}, \frac{1}{4}\right)\) |
Choose the correct answer from the options given below :