If the eccentricity of the hyperbola
$\frac {x^2}{a^2}-\frac {y^2}{b^2}=1$ is $\frac {5}{4}$ and $2x + 3y -6 = 0$
is a focal chord of the hyperbola, then the length of transverse axis is equal to
Given hyperbola has focus $(a e, 0)$ which will lie on $2 x+3 y-6=0$ as it is focal chord. $\therefore 2 a e-6=0 $ $\Rightarrow a e=3$ $\Rightarrow a \times \frac{5}{4}=3$ $\left[\because e=\frac{5}{4}\right]$ $\Rightarrow a=\frac{12}{5}$ $\therefore$ Length of transverse axis $=2 a$ $=2 \times \frac{12}{5}=\frac{24}{5}$