Question:

If \( p(y) = (y+1)(y^3+2)(y^4+6) \) and \( g(y) = y^2 - 3y +1 \), then the degree of \( \frac{p(y)}{g(y)} \) is:

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The degree of a product of polynomials is the sum of their degrees. The degree of a rational function \( \frac{p(x)}{g(x)} \) is: \[ \text{Degree} = \text{Degree of numerator} - \text{Degree of denominator}. \]
Updated On: Oct 27, 2025
  • \( 6 \)
  • \( 3 \)
  • \( 5 \)
  • \( 4 \)
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The Correct Option is A

Solution and Explanation

The degree of a polynomial is the highest power of \( y \).
- Degree of \( p(y) \):
\[ (y+1) \Rightarrow \text{Degree } 1. \] \[ (y^3+2) \Rightarrow \text{Degree } 3. \] \[ (y^4+6) \Rightarrow \text{Degree } 4. \] \[ \text{Total Degree of } p(y) = 1 + 3 + 4 = \] - Degree of \( g(y) \):
\[ y^2 - 3y + 1 \Rightarrow \text{Degree } 2. \] Thus, the degree of \( \frac{p(y)}{g(y)} \) is:
\[ 8 - 2 = 6. \]
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