Question:

If one zero of the polynomial \( (a+2)x^2 - 3ax -2 \) is negative of the other, then find the polynomial.

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For opposite roots, sum of roots must be zero.
Updated On: Oct 27, 2025
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Solution and Explanation

Let the roots be \( \alpha \) and \( -\alpha \).
Sum of the roots:
\[ \alpha + (-\alpha) = 0 = -\frac{-3a}{a+2}. \] \[ \Rightarrow \frac{3a}{a+2} = 0 \Rightarrow 3a = 0 \Rightarrow a = 0. \] Thus, the polynomial simplifies to:
\[ (x^2 - c^2). \]
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