Given:
\(x^2 - x - 1 = 0 \implies \alpha, \beta \text{ are roots.}\)
The relation between \(\alpha\) and \(\beta\) is:
\(\alpha^2 = \alpha + 1, \quad \beta^2 = \beta + 1.\)
The sequence \(S_n\) is defined as:
\(S_n = 2023\alpha^n + 2024\beta^n.\)
Using the recurrence relation for the roots:
\(S_{n+2} = S_{n+1} + S_n.\)
Applying this for \(n = 10\):
\(S_{12} = S_{11} + S_{10}.\)
The Correct answer is: \( 2S_{11} = S_{12} + S_{10} \)
If \(\sum\)\(_{r=1}^n T_r\) = \(\frac{(2n-1)(2n+1)(2n+3)(2n+5)}{64}\) , then \( \lim_{n \to \infty} \sum_{r=1}^n \frac{1}{T_r} \) is equal to :
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to: