Given: A string suspended from the ceiling is subjected to two downward forces \( F_1 \) and \( F_2 \), resulting in lengths \( L_1 \) and \( L_2 \) respectively. We are asked to find the actual length of the string.
Concept: The actual length \( L \) of the string is related to the forces applied to it. The string follows Hooke's law, which states that the extension or compression in the string is proportional to the applied force. When two different forces \( F_1 \) and \( F_2 \) cause different extensions \( L_1 \) and \( L_2 \), we can use the principle of superposition to calculate the actual length of the string.
Approach: - The forces \( F_1 \) and \( F_2 \) are proportional to the extensions \( L_1 \) and \( L_2 \), respectively. This means the relationship between force and extension can be expressed as: \[ \frac{F_2 - F_1}{L_2 - L_1} = \text{constant}. \] This constant is the stiffness of the string. - The actual length \( L \) is the length corresponding to zero force, which can be calculated by the formula: \[ L = \frac{F_2 L_1 - F_1 L_2}{F_2 - F_1}. \]
Final Answer: The actual length of the string is given by: \[ L = \frac{F_2 L_1 - F_1 L_2}{F_2 - F_1}. \]
\( x \) is a peptide which is hydrolyzed to 2 amino acids \( y \) and \( z \). \( y \) when reacted with HNO\(_2\) gives lactic acid. \( z \) when heated gives a cyclic structure as below:

A steel wire of length 2 m and Young's modulus \( 2.0 \times 10^{11} \, \text{N/m}^2 \) is stretched by a force. If Poisson's ratio and transverse strain for the wire are \( 0.2 \) and \( 10^{-3} \) respectively, then the elastic potential energy density of the wire is \( \times 10^6\), in SI units .
Two slabs with square cross section of different materials $(1,2)$ with equal sides $(l)$ and thickness $\mathrm{d}_{1}$ and $\mathrm{d}_{2}$ such that $\mathrm{d}_{2}=2 \mathrm{~d}_{1}$ and $l>\mathrm{d}_{2}$. Considering lower edges of these slabs are fixed to the floor, we apply equal shearing force on the narrow faces. The angle of deformation is $\theta_{2}=2 \theta_{1}$. If the shear moduli of material 1 is $4 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$, then shear moduli of material 2 is $\mathrm{x} \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$, where value of x is _______ .
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of:
