Question:

If \(A=\begin{bmatrix} -2&6\\-5&-1\end{bmatrix}\) then \(A^{-1}\) is:

Updated On: May 21, 2024
  • \(\frac{1}{28}\begin{bmatrix} 2&-5\\6&-1\end{bmatrix}\)
  • \(\frac{1}{32}\begin{bmatrix} -1&6\\-5&-2\end{bmatrix}\)
  • \(\frac{1}{32}\begin{bmatrix} -1&-6\\5&-2\end{bmatrix}\)
  • \(\frac{-1}{28}\begin{bmatrix} -1&-6\\-5&-2\end{bmatrix}\)
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The Correct Option is C

Solution and Explanation

The correct option is (C):\(\frac{1}{32}\begin{bmatrix} -1&-6\\5&-2\end{bmatrix}\)
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