A scalar matrix is a matrix in which all the diagonal elements are equal, and all the off-diagonal elements are zero.
The given matrix $A$ is: \[ A = \begin{pmatrix} -1 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 5 \end{pmatrix} \] This matrix is not a scalar matrix because its diagonal elements are not all equal. Thus, we rule out the scalar matrix option.
Next, we observe that a symmetric matrix is one where $A = A^T$, and a skew-symmetric matrix is one where $A = -A^T$.
The given matrix $A$ is neither symmetric nor skew-symmetric, as it is not equal to its transpose and also not equal to the negative of its transpose. Therefore, the correct answer is that $A$ is a scalar matrix.
If \[ A = \begin{bmatrix} 1 & 2 & 0 \\ -2 & -1 & -2 \\ 0 & -1 & 1 \end{bmatrix} \] then find \( A^{-1} \). Hence, solve the system of linear equations: \[ x - 2y = 10, \] \[ 2x - y - z = 8, \] \[ -2y + z = 7. \]