Question:
If $a , b$ and $c$ are three non-coplanar vectors and $p , q$ and $r$ are vectors defined by $p =\frac{ b \times c }{[ a b c ]}, q =\frac{ c \times a }{[ a b c ]}$ and $r =\frac{ a \times b }{[ a b c ]}$, then the value of $( a + b ) \cdot p +( b + c ) \cdot q +( c + a ) \cdot r$
is equal to
If $a , b$ and $c$ are three non-coplanar vectors and $p , q$ and $r$ are vectors defined by $p =\frac{ b \times c }{[ a b c ]}, q =\frac{ c \times a }{[ a b c ]}$ and $r =\frac{ a \times b }{[ a b c ]}$, then the value of $( a + b ) \cdot p +( b + c ) \cdot q +( c + a ) \cdot r$
is equal to
Updated On: Apr 15, 2024
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The Correct Option is D
Solution and Explanation
Let $T_{1} =\left( a + b\right) � p$
$=a �p+b�p$
$a\cdot\frac{b\times c}{\left[a\,b\,c\right]}+\frac{b\cdot\left(b\times c\right)}{\left[a\,b\,c\right]}$
$\frac{\left[a\,b\,c\right]}{\left[a\,b\,c\right]}+\frac{\left[b\,b\,c\right]}{\left[a\,b\,c\right]} = 1 + 0 = 1$
Similarly, $T_{2} = \left(b + c\right). q = 1$
and $T_{3} =\left(c+a\right) �r =1$
$\therefore T_{1}+T _{2} +T _{3} =3$
$=a �p+b�p$
$a\cdot\frac{b\times c}{\left[a\,b\,c\right]}+\frac{b\cdot\left(b\times c\right)}{\left[a\,b\,c\right]}$
$\frac{\left[a\,b\,c\right]}{\left[a\,b\,c\right]}+\frac{\left[b\,b\,c\right]}{\left[a\,b\,c\right]} = 1 + 0 = 1$
Similarly, $T_{2} = \left(b + c\right). q = 1$
and $T_{3} =\left(c+a\right) �r =1$
$\therefore T_{1}+T _{2} +T _{3} =3$
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Vector Algebra
A vector is an object which has both magnitudes and direction. It is usually represented by an arrow which shows the direction(→) and its length shows the magnitude. The arrow which indicates the vector has an arrowhead and its opposite end is the tail. It is denoted as
The magnitude of the vector is represented as |V|. Two vectors are said to be equal if they have equal magnitudes and equal direction.
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Arithmetic operations such as addition, subtraction, multiplication on vectors. However, in the case of multiplication, vectors have two terminologies, such as dot product and cross product.