Question:

If A\vec{A} and B\vec{B} are non-zero vectors which obey the relation A+B=AB\left|\vec{A}+\vec{B}\right|=\left|\vec{A}-\vec{B}\right|, then the angle between them is

Updated On: Jul 5, 2022
  • 0^{\circ}
  • 60^{\circ}
  • 90^{\circ}
  • 120^{\circ}
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The Correct Option is C

Solution and Explanation

A+B=AB\left|\vec{A}+\vec{B}\right|=\left|\vec{A}-\vec{B}\right| A2+B2+2ABcosθ\left|\vec{A}\right|^{2}+\left|\vec{B}\right|^{2}+2\left|\vec{A}\right|\left|\vec{B}\right|cos \theta =A2+B22ABcosθ=\left|\vec{A}\right|^{2}+\left|\vec{B}\right|^{2}-2\left|\vec{A}\right|\left|\vec{B}\right| cos \theta cosθ=0θ=90\therefore\quad cos\theta=0 \Rightarrow \theta= 90^{\circ}
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration