Question:

If $\vec{A}$ and $\vec{B}$ are non-zero vectors which obey the relation $\left|\vec{A}+\vec{B}\right|=\left|\vec{A}-\vec{B}\right|$, then the angle between them is

Updated On: Jul 5, 2022
  • 0$^{\circ}$
  • 60$^{\circ}$
  • 90$^{\circ}$
  • 120$^{\circ}$
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The Correct Option is C

Solution and Explanation

$\left|\vec{A}+\vec{B}\right|=\left|\vec{A}-\vec{B}\right|$ $\left|\vec{A}\right|^{2}+\left|\vec{B}\right|^{2}+2\left|\vec{A}\right|\left|\vec{B}\right|cos \theta$ $=\left|\vec{A}\right|^{2}+\left|\vec{B}\right|^{2}-2\left|\vec{A}\right|\left|\vec{B}\right| cos \theta$ $\therefore\quad cos\theta=0 \Rightarrow \theta= 90^{\circ}$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration