To solve this, recall the properties of determinants and adjugates. If \( A \) is a 3×3 matrix, then \( |\text{adj}(A)| = |A|^2 \).
Similarly, for the adjugate of a scalar multiple of a matrix, use the identity \( \text{adj}(kA) = k^{n-1} \text{adj}(A) \),
where \( n \) is the order of the matrix.
Solve for \( B \) and then compute the trace and determinant to find the solution.