If
\((^{40}C_0) + (^{41}C_1) + (^{42}C_2) + ...... + (^{60}C_{20}) \frac{m}{n} ^{60}C_{20}\)
m and n are coprime, then m + n is equal to _____.
The correct answer is 102
\(^{40}C_0 + ^{41}C_1 + ^{42}C_2 + ...... + ^{60}C_{20}\)
\(= ^{40}C_{40} + ^{41}C_{40} + ^{42}C_{40} + ...... + ^{60}C_{40 }\)
\(= ^{61}C_{41}\)
\(= \frac{61}{41} . ^{60}C_{41} \)
∴ m = 61 , n = 41
Therefore , m + n = 102
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is:
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32
Permutation is the method or the act of arranging members of a set into an order or a sequence.
Combination is the method of forming subsets by selecting data from a larger set in a way that the selection order does not matter.