Question:

If
\((^{40}C_0) + (^{41}C_1) + (^{42}C_2) + ...... + (^{60}C_{20}) \frac{m}{n} ^{60}C_{20}\)
m and n are coprime, then m + n is equal to _____.

Updated On: Mar 2, 2024
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Correct Answer: 102

Solution and Explanation

The correct answer is 102
\(^{40}C_0 + ^{41}C_1 + ^{42}C_2 + ...... + ^{60}C_{20}\)
\(= ^{40}C_{40} + ^{41}C_{40} + ^{42}C_{40} + ...... + ^{60}C_{40 }\)
\(= ^{61}C_{41}\)
\(= \frac{61}{41} . ^{60}C_{41} \)
∴ m = 61 , = 41
Therefore ,  m + n = 102
 

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Concepts Used:

Permutations and Combinations

Permutation:

Permutation is the method or the act of arranging members of a set into an order or a sequence. 

  • In the process of rearranging the numbers, subsets of sets are created to determine all possible arrangement sequences of a single data point. 
  • A permutation is used in many events of daily life. It is used for a list of data where the data order matters.

Combination:

Combination is the method of forming subsets by selecting data from a larger set in a way that the selection order does not matter.

  • Combination refers to the combination of about n things taken k at a time without any repetition.
  • The combination is used for a group of data where the order of data does not matter.