If
\((^{40}C_0) + (^{41}C_1) + (^{42}C_2) + ...... + (^{60}C_{20}) \frac{m}{n} ^{60}C_{20}\)
m and n are coprime, then m + n is equal to _____.
The correct answer is 102
\(^{40}C_0 + ^{41}C_1 + ^{42}C_2 + ...... + ^{60}C_{20}\)
\(= ^{40}C_{40} + ^{41}C_{40} + ^{42}C_{40} + ...... + ^{60}C_{40 }\)
\(= ^{61}C_{41}\)
\(= \frac{61}{41} . ^{60}C_{41} \)
∴ m = 61 , n = 41
Therefore , m + n = 102
Match List-I with List-II
List-I | List-II |
---|---|
(A) \(^{8}P_{3} - ^{10}C_{3}\) | (I) 6 |
(B) \(^{8}P_{5}\) | (II) 21 |
(C) \(^{n}P_{4} = 360,\) then find \(n\). | (III) 216 |
(D) \(^{n}C_{2} = 210,\) find \(n\). | (IV) 6720 |
Choose the correct answer from the options given below:
Permutation is the method or the act of arranging members of a set into an order or a sequence.
Combination is the method of forming subsets by selecting data from a larger set in a way that the selection order does not matter.