In this reaction, the following steps occur:
Step A: Reduction of ester to aldehyde using DIBAL-H (Diisobutylaluminum hydride), a selective reducing agent that reduces esters to aldehydes without affecting other functional groups.
Step B: Aldol condensation, which involves the formation of an intramolecular aldol product. This reaction is catalyzed by NaOH (alc) (sodium hydroxide in alcoholic solution).
Step C: Reduction of the product to alcohol using Zn/HCl in the Clemmensen reduction method, which reduces aldehydes to alcohols.
Thus, the correct reagents are 4, which corresponds to:
- \( A = \text{DIBAL-H} \)
- \( B = \text{NaOH (alc)} \)
- \( C = \text{Zn/HCl} \).
The Correct Answer is: A = DIBAL-H, B = NaOH(alc), C = Zn/HCl
What is the correct IUPAC name of the following compound?
Choose the correct option for structures of A and B, respectively:
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)