In this reaction, the following steps occur:
Step A: Reduction of ester to aldehyde using DIBAL-H (Diisobutylaluminum hydride), a selective reducing agent that reduces esters to aldehydes without affecting other functional groups.
Step B: Aldol condensation, which involves the formation of an intramolecular aldol product. This reaction is catalyzed by NaOH (alc) (sodium hydroxide in alcoholic solution).
Step C: Reduction of the product to alcohol using Zn/HCl in the Clemmensen reduction method, which reduces aldehydes to alcohols.
Thus, the correct reagents are 4, which corresponds to:
- \( A = \text{DIBAL-H} \)
- \( B = \text{NaOH (alc)} \)
- \( C = \text{Zn/HCl} \).
The Correct Answer is: A = DIBAL-H, B = NaOH(alc), C = Zn/HCl
\( \text{M} \xrightarrow{\text{CH}_3\text{MgBr}} \text{N} + \text{CH}_4 \uparrow \xrightarrow{\text{H}^+} \text{CH}_3\text{COCH}_2\text{COCH}_3 \)