To determine the incorrect statement, let's analyze each option:
Alkali metals react with water to form their hydroxides: This statement is correct. Alkali metals react vigorously with water, giving hydrogen gas and forming their respective hydroxides.
The oxidation number of K in KO2 is +4.: This statement is incorrect. In potassium superoxide (KO2), potassium (K) actually has an oxidation state of +1. The oxygen molecule in KO2 is in the form of a superoxide ion (O2-), which has an oxidation state of -1/2 per oxygen atom. The potassium ion balances the charge, resulting in potassium's oxidation state remaining +1.
Ionisation enthalpy of alkali metals decreases from top to bottom in the group: This is correct. As we move down the group in the periodic table, the atomic size increases, and the outermost electron is farther from the nucleus, requiring less energy to remove, thus ionisation enthalpy decreases.
Lithium is the strongest reducing agent among the alkali metals: This statement is correct. Lithium has the highest tendency to lose its outer electron compared to other alkali metals, making it a very strong reducing agent. This is due to its high hydration energy.
Therefore, the incorrect statement is: The oxidation number of K in KO2 is +4.
Given below are two statements. 
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
