Question

• A.

  

• B.

  

• C.

  

• D.

  

Answer 1

The Correct Option is C

Reaction of \( C_6H_5Br + CH_3Br \) with \( \text{NaOH (alc.)} \) to Form B:

In the first step, the reaction of bromobenzene (\( C_6H_5Br \)) with methyl bromide (\( CH_3Br \)) in the presence of alcoholic NaOH undergoes a nucleophilic substitution to form B, which is ortho-bromophenol.

Reaction of B with \( \text{HBr (ether)} \) to Form C:

In the second step, treating ortho-bromophenol with \( \text{HBr} \) in ether leads to the formation of C, which is para-bromophenol.

Identifying the Relationship Between A and C:

Compound A (bromobenzene) and compound C (para-bromophenol) are position isomers because they differ in the position of the bromine and hydroxyl groups on the benzene ring.

Conclusion:

The structures of B and C are as shown in Option (3), and A and C are position isomers.